Question

Find the center and radius of the circle 2x² +2y²+8x-10y-15=0​

Answer 1

Answer:

x² + y² +8x+10y-7=0.........(1)

g=8/2=4,f=10/2=5

centre is(-g,-f)=A(-4,-5) which passes through required circle

2x² + 2y²-8x-12y-9=0.........(2)

x² +y²-4x-6y-9/3=0

g=-2,f=-3

centreB(2,3) which is centre of required circle

Now equation of circle:

radius =AB =√(2+4)²+(3+5)²=√36+64=10

centre=(2,3)

(x-h)²+(y-k)²=r²

(x-2)²+(y-3)²=10²

x²+ y² -4x-6y+4+9-100=0

x² +y²-4x-6y-87=0