Question

find the center and the radius of the circle x^2+y^2+8x+10y-8=0​

Answer 1

Step-by-step explanation:

this can be found by square completion method

${x}^{2} + 8x + {y}^{2} + 10y = 8 \\ {x}^{2} + 8x + 16 + {y}^{2} + 10y + 25 = 8 + 16 + 25 \\ {( x + 4)}^{2} + {(y + 5)}^{2} = 49$

equation of circle with center(h,k) and radius r is

${(x - h)}^{2} + {(y - k)}^{2} = {r}^{2}$

therefore ,here centre of circle(-4,-5) and radius =7