Find the center of gravity of the inverted T section with flendge 60m×10 mm and web 50 mm ×10 mm
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Answered by
4
Answer:
Ans. 115 mm
Explanation:
Answered by
4
Answer:
Flange
A1=60mm×10mm
=600mm²
Y1= 10/2=5mm
Web
A2= 50mm×10mm
= 500mm²
Y2=10+50/2
= 35mm
Centre of gravity=(A1Y1+A2Y2)/A1+A2
=(600×5)+(500×35)/600+500
=18.53 mm
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