Question

Find the center of the circle with (-1,2) and (3, -2) as the ends of a diameter.​

Answer 1

Answer:

One end of the diameter of the circle =(3,2)

Center of the circle =(0,0)

Let, the other end of the diameter of the circle =(x,y)

Since the center is the mid-point of the diameter of the circle

(0,0)=(

2

3+x

,

2

2+y

)

⇒

2

3+x

=0 and

2

2+y

=0

⇒3+x=0 and 2+y=0

⇒x=−3 and y=−2

Hence, the other end of the diameter of the circle is (−3,−2)