Question

find the centre and radius of a circle with the equation 2x^2 +2y^2 -x = 0​

Answer 1

Answer:

centre is (-1/2,0) and radius is 1/2

Step-by-step explanation:

given equation of circle is 2x²+2y²-x=0 . it is in the form of x²+y²+2gx+2fy+C=0. now centre=(-g,-f)=(-1/2,0). and radius=√g²+f²-c = √1/4+0-0 = 1/2