Question

Find the centre of a circle passing through the points (6,-6) (3,-7) and (3,3).​

Answer 1

Answer:

Let O(x,y) is the center of the circle and A(6.−6),B(3,−7) and C(3,3)are the points on the circumference of the circle.

∴OA=(x1−x2)2+(y1−y2)2

⇒OA=(x−6)2+(y+6)2

⇒OB=(x−3)2+(y+7)2

⇒OC=(x−3)3+(y−3)2

∵ Radii of the circle are equal 

∴OA=OB

⇒(x−6)2+(y+6)2=(x−3)2+(y+7)2

⇒x2+36−12x+y2+36+12y=x2+9−

Answer 2

x²+y²+2gx+2fy+c=0

Substitute the value of x and y

Solve the three simultaneous eqns

U'll get the value of g and f

-g, -f would be ur answer