Find the centre of mass of a uniform plate having semicircular inner and outer boundaries
Answers
Answered by
0
Answer:
Centre of mass at y
= [(πR₂²/2)(4R₂/3π) - (πR₁²/2)(4R₁/3π)] / [(πR₂²/2) - (πR₁²/2)]
= [(2/3)R₂³ - (2/3)R₁³] / [π/ 2(R₂² - R₁²)]
= [4(R₂-R₁)(R₂² + R₁² + R₁R₂)] / [3π(R₂-R₁)(R₂+R₁)]
= [4(R₂² + R₁² + R₁R₂)] / [3π (R₁ + R₂)]
[4(R₂² + R₁² + R₁R₂)] / [3π (R₁ + R₂)] above the centre.
Hope it helps!
Similar questions