Question

The maximum diameter of the hole that can be punched from a plate of maximum shear stress 1/4th of its maximum crushing stress of punch, is equal to (where t = thickness of the plate)

Answer 1

Maximum shear stress  = 1/4th of its maximum crushing stress of punch

Thickness of the plate = t  

According to the formula of shear stress -

Shear stress = force/area.

Area = length*thickness.

Thus,  

= 1/4 shear stress = l × t.

Stress = 4 × t × l

Therefore, the stress for the maximum diameter of the hole that can be punched will be 4tl.