Math, asked by vabishyasinha, 11 months ago

find the centroid of a triangle ABC whose vertices are (- 1,0 ),(5,- 2) and( 8,2)​

Answers

Answered by renuagrawal393
6

Answer:

centroid of ∆=

x =  \frac{ {x}^{1}  + {x}^{2}  +  {x}^{3}  }{3} \\  =  \frac{ - 1 + 5 + 8}{3}  =  \frac{12}{3} = 4 \\  \bold{\underline{x = 4} }

y =  \frac{ {x}^{1} +  {x}^{2}  +  {x}^{3}  }{3}  \\  =  \frac{0 - 2 + 2}{3}  = 0 \\  \bold{\underline{y = 0}}

hope it helps u.....

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