Question

Find the centroid of a triangle ABC whose vertices are A(-3, 0), B (5, -2), C(-8, 5)

Answer 1

Given: A triangle ABC, formed by the points A(-3, 0), B(5, -2) and C(-8, 5).

To find: The centroid of the triangle.

Answer:

Formula to find the centroid of the triangle:

$\tt Centroid\ =\ \Bigg(\dfrac{x_1\ +\ x_2\ +\ x_3}{3},\ \dfrac{y_1\ +\ y_2\ +\ y_3}{3}\Bigg)$

From the points given, we have:

$\tt x_1\ =\ -3\\\\x_2\ =\ 5\\\\x_3\ =\ -8\\\\y_1\ =\ 0\\\\y_2\ =\ -2\\\\y_3\ =\ 5$

Using them in the formula,

$\tt Centroid\ =\ \Bigg(\dfrac{-3\ +\ 5\ +\ -8}{3},\ \dfrac{0\ +\ -2\ +\ 5}{3}\Bigg)\\\\\\Centroid\ =\ \Bigg(\dfrac{-6}{3},\ \dfrac{3}{3}\Bigg)\\\\\\Centroid\ =\ \Bigg(-2,\ 1\Bigg)$

Therefore, the centroid of the triangle formed by the points A(-3, 0), B(5, -2) and C(-8, 5) is (-2, 1).

Answer 2

Answer:

Step-by-step explanation:

centroid =(x1+x2+x3)\3

(y1+y2+y3)\3 is

the formula

substitute the values with this formula  hope this will help u