Question

Find the centroid of a triangle whose vertices are( -2 ,0) ,(5,4) and (-3,1)

Answer 1

Answer:

CENTROID G=( $\frac{x1+x2+x3}{3} \frac{y1+y2+y3}{3}$)

G=$(\frac{-2+5-3}{3} , \frac{0+4+1}{3} )\\\\(0, \frac{5}{3} )$

Answer 2

$\bold{Answer} \\ \green{\tt{ \therefore coordinate\:of\:centroid = (0,\frac{5}{3})}}$

• From the given question :

$\bold{Step-by-step \: explanation} \\ \\ \text{According \: to \: centroid \: formula} \\ \tt \to x = \frac{ x_{1} + x_{2} + x_{3} }{3} \\ \\ \tt \to x = \frac{ 2+5-3}{3} \\ \\ \tt \to x = \frac{5-5}{3} \\ \\ \green{\tt \to x = 0} \\ \\ \tt \to y = \frac{ y_{1} + y_{2} + y_{3} }{3} \\ \\ \tt \to y = \frac{0+4+1}{3} \\ \\ \tt \to y= \frac{ 4+1}{3} \\ \\ \green{\tt \to y= \frac{5}{3}} \\ \\ \green{\tt{\therefore Coordinate \: of \: centroid \: is \: (0, \frac{5}{3})} }$