Question

find the centroid of a triangle whose vertices are (3,4) (-7,-2) and (10,-5)

Answer 1

Centroid = x1+x2+x3/3 , y1+y2+y3/3
Centroid of x = 3-7+10/3
= 2
Centroid of y = 4-2-5/3
= -1
Centroid of triangle = (2, -1)

Answer 2

$\red{\bold{\underline{\underline{Answer}}}}$

$\bf{\green{\therefore{Centroid=(0,3)}}}$

$\pink{\bold{\underline{Step-by-step\:explanation}}}$

• Given

$\tt \implies Coordinate \: of \: p = (3,-7) \\ \\ \tt \implies Coordinate \: of \: q= (-8,6) \\ \\ \tt \implies Coordinate \: of \: r= (5,10)$

• To find

$\tt \implies Centroid = ?$

For finding value of centroid :

$\tt \implies x = \frac{ x_{1} + x_{2} + x_{3} }{3} \\ \\ \tt \implies x = \frac{3-8+5}{3} \\ \\ \tt \implies x = 0 \\ \\ \tt \implies y=\frac{ y_{1} + y_{2} + y_{3} }{3} \\ \\\tt \implies y= \frac{-7 + 6+10}{3} \\ \\ \tt \implies y= 3 \\ \\ \green{\tt \therefore Centroid \: is \: (0,3)}$