Question

find the centroid of the triangle whoese vertices was4,7 8,4 7,11​

Answer 1

Answer:

Let the Points (4,7), (8,4), and (7,11) be P(x₁, y₁), Q(x₂,y₂), and R(x₃,y₃) respectively.

Now, Using the Formula,

G(x,y) = [ (x₁ + x₂ + x₃)/3 , (y₁ + y₂ + y₃)/3 ]

= [(4 + 8 + 7)/3 , (7 + 4 + 11)/3]

= [19/3 , 22/3]

= (19/3, 22/3)

Hence, the co-ordinates of the Point G is (19/3, 22/3).

Hope it helps✌️

Answer 2

Step-by-step explanation:

$\tt\red{ANSWER}$

Let the Points (4,7), (8,4), and (7,11) be P(x₁, y₁), Q(x₂,y₂), and R(x₃,y₃) respectively. Hence, the co-ordinates of the Point G is (19/3, 22/3).

Hope it helps