find the centroid of the triangle whose vertices are (a,0),(0,a) and (a,a)
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Answer:
The coordinates of the centroid of the triangle are ( 2a / 3, 2a / 3 ).
Step-by-step-explanation:
Let the triangle be ABC.
The coordinates of the given points are
- A ( a, 0 ) ≡ ( x₁, y₁ )
- B ( 0, a ) ≡ ( x₂, y₂ )
- C ( a, a ) ≡ ( x₃, y₃ )
We have to find the coordinates of the centroid of the triangle.
Let the coordinates of centroid be G ( x, y ).
By centroid formula,
- x = ( x₁ + x₂ + x₃ ) / 3
- y = ( y₁ + y₂ + y₃ ) / 3
Now,
x = ( x₁ + x₂ + x₃ ) / 3
⇒ x = ( a + 0 + a ) / 3
⇒ x = ( a + a ) / 3
⇒ x = 2a / 3
Now,
y = ( y₁ + y₂ + y₃ ) / 3
⇒ y = ( 0 + a + a ) / 3
⇒ y = 2a / 3
∴ G ( x, y ) ≡ ( 2a / 3, 2a / 3 )
∴ The coordinates of the centroid of the triangle are ( 2a / 3, 2a / 3 ).
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