Question

find the centroid of triangle ABC whose vertices are A(3,-2) B(5,1) C(-4,-1)

Answer 1

→A(3,-2)
x1=3
y1=-2

→B(5,1)
x2=5
y2=1

→C(-4,1)
x3=-4
y3=1

x=x1+x2+x3÷3
x=3+5+(-4)÷3
→x=4/3

y=y1+y2+y3÷3
y=-2+1+(-1)÷3
→y=-2/3

→Centroid is (x,y)=(4/3,-2/3)

Answer 2

Ans: Formula for centroid:
x= x1 + x2+x3 /3
y= y1+ y2+y3 / 3

x = 3 + 5 +(-4) /3 = 4/3

y= -2 + 1 + (-1) /3 = -2/3

centroid = (4/3, -2/3)

Hope it helps...!!