Question

The angle of elevation of a cloud of a point 60m above a lake the angle is 30' at the angle of depression of the refraction of cloud in the lake is 60'

Answer 1

Let AO=H
CD=OB=60m
A'B=AB=(60+H)m

In triangke AOD,
tan30°=AO/OD=H/OD

H=OD/√3
OD=√3 H

Now, in triangle A'OD,
tan60° =OA'/OD=(OB+BA')/OD
√3=(60+60+H)/√3 H
    =(120+H)/√3 H
 =>120+H=3H
      2H=120
       H=60m

Therefore,
Height of the cloud above the lake = AB+A'B
                                                                 =(60+60)
                                                                 = 120m

HOPE IT HELPS!!!
Pls Mark as Brainliest!!