Question

Find the chance of throwing a 5 or 6 atleast once in four throws of a single die

Answer 1

the answer should be 12

Answer 2

Answer:

In one throw of dice, we have  2 /6

i.e.,  

1/3 chance of throwly a dice for five or  6

So, we have  2/3

chance of not throwing  5or  6

For four throws of dice, the chance of not rolling  5or  6

is then  2/3×2/3×2/3×2/3=1681

Probability that you will through  5or  6

atleast once  =81−16/81=65/81