Question

Find the change in kinetic energy of 1 mole of an ideal gas when temperature change by 50 degree celcis

Answer 1

As we know the Kinetic gas equation is ::-

PV = 1/3mnUrms²

Here P is pressure on the gas ,

V is the volume occupied ,

m be the mass of the gas molecule ,

n is number of moles of the gas and Urms² is the root mean square Velocity.

Also:-

Kinetic energy (K.E) of n moles of a gas = n×3/2RT

Change in kinetic energy (K.E) = Kf - Ki

As the formula for K.E is 3/2RT.

Therefore:-

According to the question,

➨ K.E = 3/2 R(T+50)-3/2RT

➨ K.E = 3/2R(T - T+50) J

➨ K.E = 3/2× 8.314×50 J

➨ K.E = 623.55 J