find the change in length of a second pendulum if the acceleration due to gravity at the place changes from 9.75 meters per second square to 9.8 meters per second square.
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this is the required answer
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Answered by
13
Answer:
0.005
Explanation:
We know that T=2 seconds
T=2π√l/g
2=2π√l/g
L= g/π²
L1= 9.75/π²
L2=9.8/π²
∆L= L1-L2
∆L=1/π² (9.8-9.75)
∆L= 0.005 π²=10 (approx)
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