Find the change in work done of a system which have aq as 1500 cal as 1 mole of an ideal gas is heated from 27°C to 327°C at constant volume is [Cv = 3]
Answers
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Given: Change in heat(aq) is 1500 cal. 1 mole of an ideal gas(Cv=3) is heated from 27°C to 327°C at constant volume
To find: Change in work done
Explanation: First we change temperature from °C to Kelvin.
Initial temperature= 27°C= 27+273 K
= 300 K
Final temperature= 327°C= 327+ 273 K
= 600 K
Change in temperature(T)= 600-300= 300 K
Number of moles= 1
Cv= 3
Change in internal energy= nCvT
= 1* 3 * 300
= 900 J
We need to convert Joule into calories.
1 cal= 4.184 J
900 J= 900/4.184 cal
= 215 cal
The relation that links change in internal energy, change in heat and change in work done is:
Change in internal energy= Change in heat + change in work
=> change in work= change in internal energy - change in heat
= 215-1500 cal
= -1285 cal
Therefore, the change in work done of system in this case is -1285 calories.