Chemistry, asked by arihanthreddy5, 4 hours ago

Find the change in work done of a system which have aq as 1500 cal as 1 mole of an ideal gas is heated from 27°C to 327°C at constant volume is [Cv = 3]​

Answers

Answered by manojkumarjunnu
0

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Answered by GulabLachman
0

Given: Change in heat(aq) is 1500 cal. 1 mole of an ideal gas(Cv=3) is heated from 27°C to 327°C at constant volume

To find: Change in work done

Explanation: First we change temperature from °C to Kelvin.

Initial temperature= 27°C= 27+273 K

= 300 K

Final temperature= 327°C= 327+ 273 K

= 600 K

Change in temperature(T)= 600-300= 300 K

Number of moles= 1

Cv= 3

Change in internal energy= nCvT

= 1* 3 * 300

= 900 J

We need to convert Joule into calories.

1 cal= 4.184 J

900 J= 900/4.184 cal

= 215 cal

The relation that links change in internal energy, change in heat and change in work done is:

Change in internal energy= Change in heat + change in work

=> change in work= change in internal energy - change in heat

= 215-1500 cal

= -1285 cal

Therefore, the change in work done of system in this case is -1285 calories.

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