Question

Find the charge of 48 g of Mg^2+ ions in Coulombs

Answer 1

Firstly find the total no. of ions. ie., 6.022×10²³×2=12.044×10²³no. of ions.
Charge of one ion in Coulombs=2×1.6×10⁻¹⁹C=3.2×10⁻¹⁹C
Total Charge in Coulombs=12.044×10²³×3.2×10⁻¹⁹C
                                         =38.5408×10⁴C
                                         ~38.54×10⁴C

Answer 2

this is the answer.

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