Chemistry, asked by pankaj7191, 11 months ago

Find the charges on the four capacitors of capacitances 1 μF, 2 μF, 3 μF and 4 μF shown in the figure (32-E32).
Figure

Answers

Answered by shilpa85475
3

Explanation:

The capacitors attain steady state when they are fully charged and when no current flows via them. Then, the circuit’s equivalent resistance,

Reff = 3 \times 63 + 6 = 2 Ω

The circuit has the current flowing,

i = 62 = 3 A

There will be the division of current i in the resistance’s inverse ratio in every branch. One branch has 3 Ω resistance and the other branch has 6 Ω resistance.

Through the 3 Ω branch, current i’  

i’ = 69i = 2 A

Through the 6 Ω branch, current i”  

i” = 1 A

  • Across the 1 Ω resistor, the voltage = 1 Ω \times 2 A = 2 V
  • On the 1 μF capacitor, the charge = 1 μF \times 2 = 2 μC
  • Across the 2 Ω resistor, the voltage = 2 A \times 2 Ω = 4 V
  • On the 2 μF capacitor, the charge = 2 μF \times 4V = 8 μC
  • Across every 3 Ω resistor, the voltage = 1 A \times 3 Ω = 3 V
  • The 3 μF capacitor has the charge = 3 μC \times 3 = 9 μC
  • The 4 μF capacitor has the charge = 4 μC \times 3 = 12 μC
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