How many time constants will elapse before the current in a charging RC circuit drops to half of its initial value? Answer the same question for a discharging RC circuit.
Answers
Answered by
0
The number of time constants are 0.69 in the charging RC circuit before the current in the charging RC circuit drops to half of the initial value.
Explanation:
Across a capacitor, the charge growth is
q = Q2 = Q1 – e - tRCq
⇒Q2 = Q 1-e-tRC
⇒12 = 1-e-tRC
⇒tRC = ln 2
Let t = nRC
⇒nRCRC = 0.69
⇒n = 0.69
Across the capacitor, the charge decay is
q = Qe-tRCq = Q2
⇒Q2 = Qe – tRC
⇒nRCRC = ln 2
⇒n = 0.69
Similar questions