Question

find the circumcentre of the triangle whose sides are 3x-y-5=0;x+2y-4=0 and 5x+3y+1=0

Answer 1

Answer:

A

3x−y−5=0

⇒y=3x−5

B

x+2y−4=0

y= -1/2x+2

C

5x+3y+1=0

y= -5/3x-1/3

D

3x−5= -1/2x+2

⇒D(2,1)

E

3x−5=-5/3x-1/3

⇒E(1,−2)

F

-1/2x+2=-5/3x-1/3

⇒F(−2,3)

Use these point to make a circle.

D=(2−h)^2+(1−k)^2=r^2

E=(1−h)^2+(−2−k)^2=r^2

F=(−2−h)^2+(3−k)^2 =r^2

=> h= -6/7, k=2/7, r=5√17/7

Circumcenter=(-6/7, 2/7) w