Math, asked by divyanadhan, 4 months ago

find the circumcentre of the triangle whose sides are x+y=0 2x+y+5=0 x-y=2​

Answers

Answered by joshuaMJ
0

Answer:

Step-by-step explanation:

3x−y−5=0

⇒y=3x−5

B

x+2y−4=0

y=  

2

−1

x+2

C

5x+3y+1=0

y=  

3

−5

x−  

3

1

 

D

3x−5=  

2

−1

x+2

⇒D(2,1)

E

3x−5=  

3

−5

x−  

3

1

 

⇒E(1,−2)

F

2

−1

x+2=  

3

−5

x−  

3

1

 

⇒F(−2,3)

Use these point to make a circle.

D=(2−h)  

2

+(1−k)  

2

=r  

2

 

E=(1−h)  

2

+(−2−k)  

2

=r  

2

 

F=(−2−h)  

2

+(3−k)  

2

=r  

2

 

⇒h=  

7

−6

,k=  

7

2

,r=  

7

5  

17

 

 

Circumcenter=(  

7

−6

,  

7

2

)

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