three men and six women can complete the same work in five days. the work done by eleven woman is equal to the work of how many men
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Answer:
10
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3 men and 7 women can complete work in 10 days but 4 men and 6 women need 8 days. In how many days will 10 women complete the same work?
3 men and 7 women can complete work in 10 days but 4 men and 6 women need 8 days. In how many days will 10 women complete the same work?Let’s write the problem as 2 equations. On a daily basis, the first group does 1/101/10 of the work and the second group performs 1/81/8:
3 men and 7 women can complete work in 10 days but 4 men and 6 women need 8 days. In how many days will 10 women complete the same work?Let’s write the problem as 2 equations. On a daily basis, the first group does 1/101/10 of the work and the second group performs 1/81/8:(1) 3m+7w=1/103m+7w=1/10
3 men and 7 women can complete work in 10 days but 4 men and 6 women need 8 days. In how many days will 10 women complete the same work?Let’s write the problem as 2 equations. On a daily basis, the first group does 1/101/10 of the work and the second group performs 1/81/8:(1) 3m+7w=1/103m+7w=1/10(2) 4m+6w=1/84m+6w=1/8
3 men and 7 women can complete work in 10 days but 4 men and 6 women need 8 days. In how many days will 10 women complete the same work?Let’s write the problem as 2 equations. On a daily basis, the first group does 1/101/10 of the work and the second group performs 1/81/8:(1) 3m+7w=1/103m+7w=1/10(2) 4m+6w=1/84m+6w=1/8We will try to eliminate the mm, because we are looking for an answer for 10w10w. Multiplying equation (1) on both sides with 4 and (2) with 3, gives us:
3 men and 7 women can complete work in 10 days but 4 men and 6 women need 8 days. In how many days will 10 women complete the same work?Let’s write the problem as 2 equations. On a daily basis, the first group does 1/101/10 of the work and the second group performs 1/81/8:(1) 3m+7w=1/103m+7w=1/10(2) 4m+6w=1/84m+6w=1/8We will try to eliminate the mm, because we are looking for an answer for 10w10w. Multiplying equation (1) on both sides with 4 and (2) with 3, gives us:(3) 12m+28w=4/1012m+28w=4/10
3 men and 7 women can complete work in 10 days but 4 men and 6 women need 8 days. In how many days will 10 women complete the same work?Let’s write the problem as 2 equations. On a daily basis, the first group does 1/101/10 of the work and the second group performs 1/81/8:(1) 3m+7w=1/103m+7w=1/10(2) 4m+6w=1/84m+6w=1/8We will try to eliminate the mm, because we are looking for an answer for 10w10w. Multiplying equation (1) on both sides with 4 and (2) with 3, gives us:(3) 12m+28w=4/1012m+28w=4/10(4) 12m+18w=3/812m+18w=3/8
3 men and 7 women can complete work in 10 days but 4 men and 6 women need 8 days. In how many days will 10 women complete the same work?Let’s write the problem as 2 equations. On a daily basis, the first group does 1/101/10 of the work and the second group performs 1/81/8:(1) 3m+7w=1/103m+7w=1/10(2) 4m+6w=1/84m+6w=1/8We will try to eliminate the mm, because we are looking for an answer for 10w10w. Multiplying equation (1) on both sides with 4 and (2) with 3, gives us:(3) 12m+28w=4/1012m+28w=4/10(4) 12m+18w=3/812m+18w=3/8Subtracting (3) with (4) gives:
3 men and 7 women can complete work in 10 days but 4 men and 6 women need 8 days. In how many days will 10 women complete the same work?Let’s write the problem as 2 equations. On a daily basis, the first group does 1/101/10 of the work and the second group performs 1/81/8:(1) 3m+7w=1/103m+7w=1/10(2) 4m+6w=1/84m+6w=1/8We will try to eliminate the mm, because we are looking for an answer for 10w10w. Multiplying equation (1) on both sides with 4 and (2) with 3, gives us:(3) 12m+28w=4/1012m+28w=4/10(4) 12m+18w=3/812m+18w=3/8Subtracting (3) with (4) gives:(5) 10w=16/40−15/40=1/4010w=16/40−15/40=1/40
3 men and 7 women can complete work in 10 days but 4 men and 6 women need 8 days. In how many days will 10 women complete the same work?Let’s write the problem as 2 equations. On a daily basis, the first group does 1/101/10 of the work and the second group performs 1/81/8:(1) 3m+7w=1/103m+7w=1/10(2) 4m+6w=1/84m+6w=1/8We will try to eliminate the mm, because we are looking for an answer for 10w10w. Multiplying equation (1) on both sides with 4 and (2) with 3, gives us:(3) 12m+28w=4/1012m+28w=4/10(4) 12m+18w=3/812m+18w=3/8Subtracting (3) with (4) gives:(5) 10w=16/40−15/40=1/4010w=16/40−15/40=1/40So, on a daily basis, 10 women do 1/401/40 of the work or 10 women need 40 days to complete the job.