Find the circumference of awheel that makes 1130revolutions to go 2km.33dm.91dm
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Distance covered in 1130 revolutions = 2.0124 km
" ". " 1. ". =(2.124÷1130 ) km =100 ( suppose )
Circumference of circle = 2πr
therefore A.P.Q 100=2×22÷7×r
or …....
and then you solve it
hope it helps you.
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