Question

Find the circumference of the circle ,if its radius is 14 cm.​

Answer 1

Circumference = $2\pi r$

Radius = 14 cm

Therefore, circumference = 2 x $\frac{22}7}$ x 14

= 2 x 22 x 2 cm

= 88 cm

Hope it is correct.

Answer 2

Step-by-step explanation:

Question :-

• Find the circumference of circle whose radius is 14 cm.

To Find :-

• Circumference of circle.

Solution :-

Given :

• Radius = 14 cm

By using the formula,

${\longrightarrow{\sf Circumference\ of\ circle\ =\ 2 \pi r}}$

Where,

• r = radius of the circle

According to the question, by using the formula, we get :

${\longrightarrow{\sf Circumference\ of\ circle\ =\ 2 \pi r}}$

${\longrightarrow{\sf 2 \times \dfrac{22}{7} \times 14}}$

${\longrightarrow{\sf 2 \times \dfrac{22}{\cancel7} \times \cancel{14}}}$

${\longrightarrow{\sf 2 \times 22 \times 2}}$

${\longrightarrow{\sf 88\ cm}}$

∴ Hence, circumference of circle is 88 cm.

More To Know :-

$\boxed{\begin {minipage}{9cm}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2 \\ \\ \star\sf Circle =\ {\pi}r^2 \end {minipage}}$