Question

Find the circumference of the circle that is within a square if the area of the square is 81 cm²

(Take $\pi$ = $\frac{22}{7}$ )

Answer 1

Hello Mate!

Since in figure, we can see that circle is inscribed inside in a square.

Area of square = side²

81 cm² = side²

√81 cm² = side

9 cm = side.

So, AB = length of diameter of circle = 9 cm,

EF ( radius of circle ) = 9 cm / 2

Circumference of circle = 2πr

= 2 × 22 / 7 × 9 / 2 cm

= 28.3 cm.

Have great future ahead!

Answer 2

Hey dear here is your answer!!!!!

___________________________

We have been told that the circle is enclosed in the circle.

That means both square and the circle have a common center.

The diameter of the circle would be equal to the side of the square.

Area of the square is 81 cm².

Also, we know that area of square is Side².

According to question:-

Side² = 81

Side = $\sqrt{81}$

Side = 9 cm

Now, the radius of the circle is $\frac{D}{2}$

So, radius would be $\frac{9}{2}$

Now, the circumference of a circle is 2πr.

Substitute the value of r :-

= 2 x $\frac{22}{7}$ x $\frac{9}{2}$

= $\frac{396}{14}$

= 28.28 cm (approx)

So, the circumference of the circle is 28.28 cm !

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❣️⭐ Hope it helps you dear...⭐⭐❣️❣️