Question

find the Cl concentration in solution which is obtained by mixing one mole each of BaCl2,NaCl and HCl in 500ml water

Answer 1

Hello Dear,

◆ Answer -

Molarity = 8 M

◆ Explaination -

# Given -

V = 500 ml = 0.5 L

# Solution -

Moles of Cl formed by mixing various salts -

Moles (Cl-) = 2×n(BaCl2) + 1×n(NaCl) + 1×n(HCl)

Moles (Cl-) = 2×1 + 1×1 + 1×1

Moles (Cl-) = 2 + 1 + 1

Moles (Cl-) = 4 mol

Concentration of chlorine ions in solution is given by -

Molarity = moles of solute / volume of solution

Molarity = 4 / 0.5

Molarity = 8 M

Therefore, concentration of Cl- in solution is 8 M.

Thanks dear...