Find the Cl concentration in solution which is obtained by mixing one mole each of BaCl2, NaCl andHCI in 500 ml water.
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◆ Answer -
Molarity = 8 M
◆ Explaination -
# Given -
V = 500 ml = 0.5 L
# Solution -
Moles of Cl formed by mixing various salts -
Moles (Cl-) = 2×n(BaCl2) + 1×n(NaCl) + 1×n(HCl)
Moles (Cl-) = 2×1 + 1×1 + 1×1
Moles (Cl-) = 2 + 1 + 1
Moles (Cl-) = 4 mol
Concentration of chlorine ions in solution is given by -
Molarity = moles of solute / volume of solution
Molarity = 4 / 0.5
Molarity = 8 M
Therefore, concentration of Cl- in solution is 8 M.
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Explanation:
8M
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