Question

Find the co-efficient of t. in 3x27x12. .​

Answer 1

Answer:

\huge \green{y = 14 \: \: or \: \: - 2}y=14or−2

Step-by-step explanation:

Let the required point be ( 0 , y ) . Note that x coordinate will be zero because point lies on y axis. Now this point is at distance 10 from ( 6 ,6 )

, so use distance formula

\begin{gathered} \sqrt{(0 - 6) {}^{2} + (y - 6) {}^{2} } = 10 \\ \\ \implies 36 + (y - 6) {}^{2} = 100 \\ \\ \implies (y - 6) {}^{2} = 100 - 36 = 64 \\ \\ \implies y - 6 = \sqrt{64} = \pm8 \\ \\ y = 6 + 8 \: \: or\: \: 6 - 8 \\ \\ y = 14 \: \: \: or \: \: - 2\end{gathered}

(0−6)

2

+(y−6)

2

=10

⟹36+(y−6)

2

=100

⟹(y−6)

2

=100−36=64

⟹y−6=

64

=±8

y=6+8or6−8

y=14or−2