Question

find the co ordinate of the point which divdes the join of (-1,7) and (7,3) in the raito2:3?
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Answer 1

(refer to the attachment)

GiveN:-

Point which divdes the join of (-1,7) and (7,3) in the raito 2:3.

To FinD:-

The co-ordinate of the point which divdes the join.

SolutioN:-

Let the point P be (x,y).

We know that section formula is,

$\large{\green{\underline{\boxed{\bf{(x,y)=\left(\dfrac{m_{1}x_{2}+m_{2}x_{1}}{m_{1}+m_{2}},\dfrac{m_{1}y_{2}+m_{2}y_{1}}{m_{1}+m_{2}}\right)}}}}}$

where,

• m1 is 2
• m2 is 3
• x1 is -1
• x2 is 7
• y1 is 7
• y2 is 3

Putting the values,

$\large\implies{\sf{(x,y)=\left(\dfrac{2.7+3.(-1)}{2+3},\dfrac{2.3+3.7}{2+3}\right)}}$

$\large\implies{\sf{(x,y)=\left(\dfrac{14+(-3)}{5},\dfrac{6+21}{5}\right)}}$

$\large\implies{\sf{(x,y)=\left(\dfrac{14-3}{5},\dfrac{27}{5}\right)}}$

$\large\implies{\sf{(x,y)=\left(\dfrac{11}{5},\dfrac{27}{5}\right)}}$

$\large\therefore\boxed{\bf{Coordinates(x,y)=\left(\dfrac{11}{5},\dfrac{27}{5}\right)}}$

Coordinates of Point P is (11/5,27/5).