Question

find the co ordinates of point (-2, 6), (3, -4) in the ratio 2:3​

Answer 1

let the point needed be of the form (x , y)

no , by section formula , we get:--

x  = m1x2 + m2x1/  m1 + m2  , y = m1y2 + m2y1/m1 + m2

x = 2*3 + 3*-2/2+3 , y = 2*-4 + 3*6/2 + 3

____answered by advik190______

x = (6 - 6)/5 , y = -8 + 18/5

x= 0 , y = 2

therefore the required point will be (0,2)