Question

Find the coefficient of performance and heat transfer rate in the condenser of a refrigerator kJ/h. which has a refrigeration capacity of 12000 kJ/h when power input is 0.75 kW.​

Answer 1

Explanation:

The coefficient of a refrigrator,

The coefficient of a refrigrator, Θ

The coefficient of a refrigrator, Θ 2

The coefficient of a refrigrator, Θ 2

The coefficient of a refrigrator, Θ 2 = The heat em over by the coed reservoir

The coefficient of a refrigrator, Θ 2 = The heat em over by the coed reservoirΘ

The coefficient of a refrigrator, Θ 2 = The heat em over by the coed reservoirΘ 1

The coefficient of a refrigrator, Θ 2 = The heat em over by the coed reservoirΘ 1

The coefficient of a refrigrator, Θ 2 = The heat em over by the coed reservoirΘ 1 = The heat sufflied to the hot reservoir

The coefficient of a refrigrator, Θ 2 = The heat em over by the coed reservoirΘ 1 = The heat sufflied to the hot reservoirC.O.P cooling =

The coefficient of a refrigrator, Θ 2 = The heat em over by the coed reservoirΘ 1 = The heat sufflied to the hot reservoirC.O.P cooling = Θ

The coefficient of a refrigrator, Θ 2 = The heat em over by the coed reservoirΘ 1 = The heat sufflied to the hot reservoirC.O.P cooling = Θ 1

The coefficient of a refrigrator, Θ 2 = The heat em over by the coed reservoirΘ 1 = The heat sufflied to the hot reservoirC.O.P cooling = Θ 1

The coefficient of a refrigrator, Θ 2 = The heat em over by the coed reservoirΘ 1 = The heat sufflied to the hot reservoirC.O.P cooling = Θ 1 −Θ

The coefficient of a refrigrator, Θ 2 = The heat em over by the coed reservoirΘ 1 = The heat sufflied to the hot reservoirC.O.P cooling = Θ 1 −Θ 2

The coefficient of a refrigrator, Θ 2 = The heat em over by the coed reservoirΘ 1 = The heat sufflied to the hot reservoirC.O.P cooling = Θ 1 −Θ 2

The coefficient of a refrigrator, Θ 2 = The heat em over by the coed reservoirΘ 1 = The heat sufflied to the hot reservoirC.O.P cooling = Θ 1 −Θ 2

The coefficient of a refrigrator, Θ 2 = The heat em over by the coed reservoirΘ 1 = The heat sufflied to the hot reservoirC.O.P cooling = Θ 1 −Θ 2 Θ

The coefficient of a refrigrator, Θ 2 = The heat em over by the coed reservoirΘ 1 = The heat sufflied to the hot reservoirC.O.P cooling = Θ 1 −Θ 2 Θ 2

The coefficient of a refrigrator, Θ 2 = The heat em over by the coed reservoirΘ 1 = The heat sufflied to the hot reservoirC.O.P cooling = Θ 1 −Θ 2 Θ 2

The coefficient of a refrigrator, Θ 2 = The heat em over by the coed reservoirΘ 1 = The heat sufflied to the hot reservoirC.O.P cooling = Θ 1 −Θ 2 Θ 2

The coefficient of a refrigrator, Θ 2 = The heat em over by the coed reservoirΘ 1 = The heat sufflied to the hot reservoirC.O.P cooling = Θ 1 −Θ 2 Θ 2

The coefficient of a refrigrator, Θ 2 = The heat em over by the coed reservoirΘ 1 = The heat sufflied to the hot reservoirC.O.P cooling = Θ 1 −Θ 2 Θ 2

The coefficient of a refrigrator, Θ 2 = The heat em over by the coed reservoirΘ 1 = The heat sufflied to the hot reservoirC.O.P cooling = Θ 1 −Θ 2 Θ 2 The coefficient of performance of a heat pump depends on its dety. The heat rejected to the hot sink is greater than the heat absorbed from the cold source.

Answer 2

The heat transfer rate in the condenser of  a $14700\frac{kj}{h}$ .

Explanation:

Refrigeration capacity,$Q_{2}=12000\frac{kj}{h}$

power input, $W=0.75kW(=0.75*60*60\frac{kj}{h})$

Heat transfer rate:

(C.O.P)refrigerator=$\frac{heat absorbed at lower temperature}{workinpu}$

$C.O.P=\frac{Q_{2}}{W}$

$=\frac{12000}{0.75*60*60}$

$=4.44$

According to the first law,

$Q_{1}=Q_{2}+W$

$=12000+0.75*60*60$

$=14700\frac{KJ}{H}$

Heat transfer rate=$14700\frac{kj}{h}$