Find the coefficient of x^2 in the expansion of (x+3)(x-1)^2
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Answer:
(x+3)(x-1)²
(x+3)[ (x)²+(1)²-2(x)(1) ]
(x+3) [ x²-2x+1 ]
x( x²-2x+1) +3 (x²-2x+1)
x³-2x²+x+3x²-6x+3
x³+x²-5x+3
Here, the coefficient of x² is 1.
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