Question

find the coefficient of x`-3 in the expansion of (x-1/2x)5​

Answer 1

Answer:

5/16

Step-by-step explanation:

Tr+1 =5Cr $x^{5-2r} (-1)^{r} (2)^{r}$ ---------(1)

From the question, $x^{5-2r} = x^{-3}$

hence r = 4

put value of r=4 in eqn (1)

T5 = $\frac{5}{16} x^{-3}$

therefore, coefficient = 5/16

Hope this helps!