Question

If logx(base a ) = log x( base b ) where a > 0 , b > 9 , a≠ b , a ≠ 1 .

find x .

Answer 1

Answer:

Step-by-step explanation:

by logarithmic identities we can write

2/loga= 1/logb+1/logc (all bases in x)

2/loga= log(bc)/(logblogc)

or loga= (logblogc2)/logbc

logc2=logbc*loga(baseb)

now raising power of x both sides

c^2= (bc)^loga(baseb)

Answer 2

Answer:

Step-by-step explanation:

by logarithmic identities we can write

2/loga= 1/logb+1/logc (all bases in x)

2/loga= log(bc)/(logblogc)

or loga= (logblogc2)/logbc

logc2=logbc*loga(baseb)

now raising power of x both sides

c^2= (bc)^loga(baseb)

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