Question

Find the coefficient of x2 and x in the product of (x – 3) (x + 7) (x – 4).
class 9 ml aggarwal

Answer 1

Multiply first (x – 3) (x + 7)

Now, x²+7x -3x - 21

x²+ 4x -21

Again Multiply ( x²+ 4x -21) (x – 4).

Now, x³ -4x² + 4x²- 16x - 21x + 84

x³ - 37x + 84

from above we conclude that,

cofficient of x² = 0

Cofficient of x = -37..

Hope it will help u..

Answer 2

Step-by-step explanation:

✿ᑕOᖇᖇᗴᑕT ᑫᑌᗴՏTIOᑎ :-

$find \: the \: coefficient \: of \: x {}^{2} \: and \: x \: in \: the \\ product \: of \: (x + 5) \: (x + 3) \: (x + 7)$

✿ᗩᑎՏᗯᗴᖇ :-

✪ՏOᒪᑌTIOᑎ:-

$(x + 5) \: (x + 3) \: (x + 7) \\ = >( x {}^{2} \: - 5x \: + 3x \: - 15) \: (x + 7)$

$(x {}^{2} - \: 2x \: - \: 15) \: (x + 7)$

$x {}^{3} \: - 2x {}^{2} - 15x + 7x {}^{2} - 14x - 105$

$x {}^{3} + 5x {}^{2} - 29x - 105$

$therefore \: the \: coefficient \: x {}^{2} \: is \: 5$

$and \: the \: coeffiient \: of \: x \: is \: - 29$