Question

Find the comman difference of an AP whose 1st term is 5 and the sum of its four terms is half the sum of the next 4 terms

Answer 1

Solution:-

a = 5.

A.T.Q.

Sum of First 4 Term.

=> a + (a + d )+ (a + 2d )+ (a + 3d)

=> 4a + 6d

=> 20 + 6d

Sum of Next 4 Term.

=> (a + 4d) + ( a + 5d) + (a + 6d) + (a + 7d)

=> 4a + 21d

=> 20 + 22d.

A.T.Q.

( 20 + 6d) = ( 20 + 22d) / 2

=> 20 + 6d = 10 + 11d

=> 11d - 6d = 20 - 10

=> 5d = 10

=> d = 2.

Answer 2

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