Question

Find the ratio in which the line segment joining the points (2,3) and (3,2) is divided by x axis.... please very urgent

Answer 1

here is your answer which you want

Answer 2

$Let \: the \: ratio \: in \:which \: the \: line \\segment \: joining \: the \: points \\A(2,3) = (x_{1}, y_{1}) \: and \\ B(3,2) = (x_{2}, y_{2})\: is \:divided \\\pink { externally} \: by \\ x - axis \: is \: k : 1$

$Let \: P(x,0) \:be \: the \: required \: point .$

$\underline { \blue { By \: section \: formula }}$

$\Big(\frac{kx_{2}-x_{1}}{k-1} ,\frac{ky_{2}-y_{1}}{k-1}\Big) = P( x , 0)$

$\frac{ky_{2}-y_{1}}{k-1} = 0$

$\implies \frac{ k\times 2 - 3}{k-1} = 0$

$\implies 2k - 3 = 0$

$\implies 2k = 3$

$\implies k = \frac{3}{2}$

$\implies k : 1 = 3 : 2$

Therefore.,

$\red { Required \: ratio } \green {= 3:2}$

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