Find the common diference of an ap whose nth term is 6n+2
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nth term given is (6n+2).
nth term =a+(n-1)d
where a=first term,n=No of terms in AP, d=common difference
(6n+2)=a+(n-1)d
(6n+2)-a=(n-1)d
d=(6n+2)-a/(n-1)
now put all the value of a,n,d....and get the answer.
nth term =a+(n-1)d
where a=first term,n=No of terms in AP, d=common difference
(6n+2)=a+(n-1)d
(6n+2)-a=(n-1)d
d=(6n+2)-a/(n-1)
now put all the value of a,n,d....and get the answer.
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