Find the common difference a An arithmetic progression series of 14 terms with common difference of 'd' and first term =14 is given to you. Now, if the sum of all the terms is equal to the square of the last term. Then find the value of a Note: Don't consider the case where the value of the common difference is zero. Note: The formula for finding sum of 'n' terms is denoted by Sn and Sn = (n/2) + (2 * (+(n-1) * d).
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Hello. Strange. In this question. We are given there are a total of 60 students. Okay. And we are given the number of the students who passed in mathematics Is given to be equal to 45. And the number of the students who passed in physics is given to be equal to 40. Okay. And we are given the number of the students who fail in both these subjects is given to be five. So I'll write this mathematically.
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Step-by-step explanation:21/2
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