Question

Find the common difference and 15th term of the A.P 125,120,115,110.......​

Answer 1

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Given that,

↪ AP : 125,120,115,110.....

LET,

• a1 = 125
• a2 = 120
• a3 = 115
• a4 = 110

Common difference (d) = a2 - a1 = a4 - a3

➡ a2 - a1 = 120 - 125 = - 5

➡ a4 - a3 = 110 - 115 = - 5

• a15 = ?

a = 125; n = 15; d = - 5

➡ an = a + (n - 1)d

➡ a15 = 125 + (15 - 1)(-5)

➡ a15 = 125 + 14(-5)

➡ a15 = 125 - 70

➡ a15 = 55

∴ Hence common difference is “ - 5 ” & a15 = 55

Step-by-step explanation:

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Answer 2

the above answer is correct....