find the common difference of an AP whose first term is 1 and the sum of the first four terms is 132 the sum of the next four terms.
4 marks question.
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Answer:
4 terms are 1, 1+d,1+2d,1+3d.
sum = 4+6d
next 4 terms are 1+4d, 1+5d,1+6d,1+7d.
sum = 4+22d
As per condition
4+22d= 3*(4+6d)= 12+18d
4d=8
d=2
Step-by-step explanation:
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