Find the common difference of an AP whose first term is 2 and the sum of the first four terms is one-third to the sum of the next four terms?
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a=2
S4 = 1/3 S8 - S4
4/2(2*2+3d)=1/3[8/2(2*2+7d)- 4/2(2*2+3d)]
8+6d=1/3[16+28d-8-6d]
8+6d=1/3(8+22d)
24+18d=8+22d
22d-18d+8-24=0
4d=16
d=4
Hope it helped you
S4 = 1/3 S8 - S4
4/2(2*2+3d)=1/3[8/2(2*2+7d)- 4/2(2*2+3d)]
8+6d=1/3[16+28d-8-6d]
8+6d=1/3(8+22d)
24+18d=8+22d
22d-18d+8-24=0
4d=16
d=4
Hope it helped you
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