Find the common difference of an AP whose first term is 5 and the sum
of its first four terms is half the sum of the next four terms
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Answered by
0
Answer:
d = 10/17
Step-by-step explanation:
Given,
a = 5
and, 4(2a-7d) = 3/2 * 2(2a-3d)
8(10-7d) = 6(10-3d)
=> 80 - 56d = 60 -18d
=> 20 = 34d
=> d = 10/17
Answered by
1
Answer:hope it is helpful...
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