Question

find the common difference of the AP whose first term is 12 and fifth term is zero​

Answer 1

Answer:

-3

Step-by-step explanation:

tn=a+(n-1)d

0=12+(4)×d

d= -3

Answer 2

The common difference is -3.

Step-by-step explanation:

Given : The AP whose first term is 12 and fifth term is zero​.

To find : The common difference  ?

Solution :

The first term of A.P is a=12.

The fifth term is A.P is $a_5=0$

The fifth term is $a_5=a+4d$

Substitute the values,

$0=12+4d$

$4d=-12$

$d=\frac{-12}{4}$

$d=-3$

Therefore, the common difference is -3.

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