Question

Find the common factor and factorise 18a3 + 14a4

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Answer 1

Answer:

We have, 10a2=2×5×a×a,

15b2=3×5×b×b

and,20c2=2×2×5×c×c

The three terms have 5 as a common factor

10a2−15b2+20c2=(2×5×a×a)−(3×5×b×b)+(2×2×5×c×c) 

=5×(2×a×a−3×b×b+4×c×c)

=5(2a2−3b2+4c2)

Answer 2

hope you have got the answer