Find the common factor and factorise 18a3 + 14a4
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We have, 10a2=2×5×a×a,
15b2=3×5×b×b
and,20c2=2×2×5×c×c
The three terms have 5 as a common factor
10a2−15b2+20c2=(2×5×a×a)−(3×5×b×b)+(2×2×5×c×c)
=5×(2×a×a−3×b×b+4×c×c)
=5(2a2−3b2+4c2)
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