find the complement of Boolean expression (A+B'+C)(A+B'C)
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Answer: a'.b.c' + a'.(b+c')
Explanation:
{(a+b'+c).(a+b'c)}'
= { (a+b'+c)' + ((a + (b'.c))' } [ apply demorgan law a'. b' = a' + b']
= { ( a'.b''.c' ) + ( a' .( b'.c)' ) } [ apply demorgan law again ]
= ( a'.b.c' ) + ( a'.(b''+c')) [ apply involution law a'' = a ]
= ( a'.b.c') + (a'.(b + c'))
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